Question 624911
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(9,3\right)]. So this means that {{{x[1]=9}}} and {{{y[1]=3}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(4,2\right)].  So this means that {{{x[2]=4}}} and {{{y[2]=2}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(2-3)/(4-9)}}} Plug in {{{y[2]=2}}}, {{{y[1]=3}}}, {{{x[2]=4}}}, and {{{x[1]=9}}}



{{{m=(-1)/(4-9)}}} Subtract {{{3}}} from {{{2}}} to get {{{-1}}}



{{{m=(-1)/(-5)}}} Subtract {{{9}}} from {{{4}}} to get {{{-5}}}



{{{m=1/5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(9,3\right)] and *[Tex \LARGE \left(4,2\right)] is {{{m=1/5}}}



<font color="red">--------------------------------------------------------------------------------------------------------------</font>
If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=I%20Need%20Algebra%20Help">jim_thompson5910@hotmail.com</a>


Also, please consider visiting my website: <a href="http://www.freewebs.com/jimthompson5910/home.html">http://www.freewebs.com/jimthompson5910/home.html</a> and making a donation. Thank you


Jim
<font color="red">--------------------------------------------------------------------------------------------------------------</font>