Question 624830
This is a simple problem. You only have to know if you will use permutation or combination. But, since position in a sequence does not matter here -- like who comes first or second -- we shall use  combination.

{{{25C12= 25!/((25-12)!(12!)) = 5,200,300 }}}

You can choose a jury in<b> 5,200,300</b> ways.