Question 624676
Solve  cosec 2θ=secθ+cotθ
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csc(2t) = sec(t) + cot(t)
1/sin(2t) = 1/cos(t) + cos(t)/sin(t)
1/(2sin*cos) = 1/cos + cos/sin
1/2 = sin + cos^2
1/2 = sin + (1 - sin^2)
2sin^2 - 2sin - 1 = 0
2x^2 - 2x - 1 = 0
*[invoke solve_quadratic_equation 2,2,-1]
sin(t) = x =~ 0.36603
theta =~ 21.47 degs (principal value)