Question 624721
The idea is to factor each piece and cancel any common factors


{{{(x^2-x-6)/(x^2-4)}}}


{{{((x-3)(x+2))/(x^2-4)}}}


{{{((x-3)(x+2))/((x-2)(x+2))}}}


{{{((x-3)*highlight((x+2)))/((x-2)*highlight((x+2)))}}}


{{{((x-3)*cross((x+2)))/((x-2)*cross((x+2)))}}}


{{{(x-3)/(x-2)}}}



So {{{(x^2-x-6)/(x^2-4)}}} fully simplifies to {{{(x-3)/(x-2)}}}