Question 624673
ln(3x+4) = 2ln(x+1)
ln(3x+4) = ln{{{(x+1)^2}}}
{{{3x+4 = (x+1)^2 }}}
{{{3x + 4 = x^2 + 1 + 2x }}}
{{{0 = x^2 - x - 3}}}

Solve this quadratic equation, we will get x = -1.30 and 2.30
Since natural logarithm is not defined on negative numbers.
Hence just x = 2.3 is the answer for this.