Question 624542
If 81% of adults enjoy beer then we will assume that the probabilty of any one randomly chosen adult enjoying beer is 0.81, this means that the probability of a randomly chosen adult not enjoying beer is 0.19.
 
Next we will assume that the probabilities of different adults liking beer are independent (one person liking beer does not depend on another liking beer).  This means that for a selection of three randomly chosen people, the probability that none of them enjoy beer is the product of the individual probabilities of them not liking beer, which is:
 
0.19*0.19*0.19 = 0.006859.