Question 624515
Find the vertex, line of symmetry, min or max and graph. F(x)-1/2(x+6)^2+2
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Given equation is that of a parabola that opens downwards (has a max).
Its form: y=-A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex.
For given equation:
vertex: (-6,2)
line of symmetry: x=-6
max at 2
see graph below:
{{{ graph( 300, 300, -10, 10, -10, 10,-.5(x+6)^2+2) }}}