Question 624573
A rectangle has an area of 240 {cm}^2 and a perimeter of 64 cm. What are its dimensions? Need to find the length and the width
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let x=length
let y=width
Area of a rectangle=length*width=xy
Perimeter=twice the length+twice the width=2x+2y
64=2x+2y
32=x+y
y=32-x
..
240=x*y=x(32-x)=32x-x^2
x^2-32x+240=0
(x-12)(x-20)=0
x=12(reject, x=length)
or
x=20
32-x=12
Dimensions of rectangle:
length=20 cm
width=12 cm