Question 624478
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Hi
find three consecutive integers {{{highlight(x)}}} , {{{highlight(x+1)}}}  ,{{{highlight(x+2)}}}  
for which the sum of the squares is 65 more than three times the square of the smallest intege
  x^2 + (x+1)^2 +(x+2)^2 = 3x^2 +65
Expand, Solve for x, List the 3 Integers.