Question 624418
To solve an equation like this one would normally factor it. But if the expression you posted does not factor:<ul><li>The greatest common factor of {{{x^3-4x^2+4x+48}}} is 1 (which we rarely bother factoring out).</li><li>{{{x^3-4x^2+4x+48}}} has too many terms for any of the factoring patterns.</li><li>{{{x^3-4x^2+4x+48}}} has too many terms for trinomial factoring</li><li>I can see no way to factor it by grouping.</li><li>The possible rational roots of {{{x^3-4x^2+4x+48}}} are:
1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 8, -8, 12, -12, 16, -16, 24, -24, 48 and -48
But <i>none</i> of these are roots.</li></ul>If there was an error in what you posted then re-post your problem. If there were no errors, then keep reading...<br>
Below are two graphs of {{{y = x^3-4x^2+4x+48}}} gives you a high-level view showing the "interesting" parts of the graph and the second one uses a differnt scale on the x-axis. This gives us a horizontally stretched view so we can better see some of the features of the graph, especially the x-intercept). (The x-intercept(s) would be the solution to your equation because x-intercepts have y values that are zero.)
{{{graph(400, 400, -100, 100, -100, 100, x^3-4x^2+4x+48)}}}
As you can see from this high-level view, the graph crosses the x-axis just once. This means that there is only one real solution to your equation. (Note: The graph does not "bend around" and come back to cross the x-axis outside of what we see here.)
{{{graph(400, 400, -10, 10, -100, 100, x^3-4x^2+4x+48)}}}
As you can see from this stretched view, the graph crosses the x-axis somewhere between -2 and -3. None of the possible rational roots were between -2 and -3. This tells us that the one real solution is an irrational number between -2 and -3.<br>
There is a formula for cubic equations but it is very complex and not often taught in Math classes. <A <HREF="http://www.math.vanderbilt.edu/~schectex/courses/cubic/">Click here</A> if you want to see it.<br>
If you have a graphing calculator and know how to use its trace function. you could find a decimal approximation for the solution to your equation. Just trace to the x-intercept.