Question 624311
log(1-2x)-2logx = 1-log(2-5x)

log(1-2x)-log(x^2) = log(10)-log(2-5x)

log((1-2x)/x^2) = log(10/(2-5x))

(1-2x)/x^2 = 10/(2-5x)

(1-2x)(2-5x)=10x^2


10x^2-9x+2 = 10x^2

-9x+2 = 0

x = 2/9

Answer: x = 2/9