Question 624204
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Hi
Find 2 consecutive integers {{{highlight(x)}}}  ,  {{{highlight(x+1)}}}  
such that 1/5 of the first minus 1/9 of the second is equal to 3
Question states***
  {{{(1/5)x + (1/9)(x+1) = 3}}}  |Multiplying thru by 45 so as all denominators = 1
  {{{9x + 5(x+1) = 135}}}    | Solve for x and list both Intergers