<PRE><B>Question 624026</B>
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4q


3q 2d 1n
3q 1d 3n
3q 0d 5n


2q 5d 0n
2q 4d 2n
2q 3d 4n


and so on...


continue the pattern until you get to 0q 0d 20n.  Then count the number of combinations.  Let me know what you come up with.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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