<PRE><B>Question 624091</B>
express as a single fraction in its simplest form:

1 1
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2x +3 4xsquared - 9
assume the problem is:
{{{1/((2x+3))}}} - {{{1/((4x^2-9))}}}
note that the 2nd denominator is the &quot;difference of squares which we can factor&quot;
{{{1/((2x+3))}}} - {{{1/((2x+3)(2x-3))}}}
you can see the common denominator will be (2x+3)(2x-3), so we have
{{{((2x-3)-1)/((2x-3)(2x+3))}}} = {{{((2x-4))/((2x-3)(2x+3))}}} = {{{(2(x-2))/((2x-3)(2x+3))}}} or {{{(2(x-2))/((4x^2-9))}}}
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