Question 7127
For division with like bases you subtract exponents, 
{{{x^a/ x^b=  X ^(a-b)}}}
For example:
{{{5^8/5^6}}}
  
gives {{{5^(8-6) = 5^2}}}.


Dividing different bases can't be simplified unless the exponents are equal. {{{x^3/y^2}}} can't be combined because it's just {{{xxx/yy}}};
 But {{{x^3/y^3}}} is {{{xxx/yyy}}}, which is {{{(x/y)(x/y)(x/y)}}}, which is {{{(x/y)^3}}}.

{{{x^a / y^a = (x/y)^a }}}