Question 623945
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,  
 y = 2(x + 2)^2 - 2  V(-2,-2), Parabola opens UP, axis of symmetry x= -2, 
and when x = 0 &#8658; y = 8-2 = 6 
{{{drawing(300,300,   -6, 6, -6, 8,  blue(line(-2,8,-2,-6))  , grid(1),
circle(-2, -2,0.3),
circle( 0, 6,0.3),
graph( 300, 300, -6, 6, -6, 8,0,2(x + 2)^2 - 2  ))}}}

___________________________________________________________________________
the vertex form of a Parabola opening Up(a>0) or Down(a<0), {{{highlight(y)=a(x-h)^2 +k}}} where(h,k) is the vertex and line of symmetry is x = h
The standard form is {{{(x -h)^2 = 4p(y -k)}}}, where  the focus is (h,k + p)

the vertex form of a Parabola opening Right(a>0) or Left(a<0), {{{highlight(x)=a(y-k)^2 +h}}} where(h,k) is the vertex and line of symmetry is y = k
The standard form is {{{(y -k)^2 = 4p(x -h)}}}, where  the focus is (h +p,k )