Question 623860
sinӨ + cosӨ = √2 sin(90-Ө) find the value of tanӨ
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sinӨ + cosӨ = √2 sin(90-Ө)
sinӨ + cosӨ = √2  cosӨ
(sinӨ + cosӨ)/ cosӨ = √2
(sinӨ/cosӨ)+(cosӨ/cosӨ)=√2
(sinӨ/cosӨ)+1=√2
tanӨ=√2-1=.414