Question 623848
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The possible rational roots of *[tex \LARGE \alpha_0 x^n\ +\ \alpha_1 x^{n-1}\ +\ \cdots\ +\ \alpha_{n-1}x\ +\ \alpha_n\ =\ 0] are all of the form  *[tex \LARGE \pm\frac{p}{q}] where *[tex \LARGE p] is an integer factor of *[tex \LARGE \alpha_n] and *[tex \LARGE q] is an integer factor of *[tex \LARGE \alpha_0]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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