<PRE><B>Question 623711</B>
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Cross-multiply and then solve the resulting linear equation for *[tex \LARGE a].


If you have already done that and got the answer 13, then you have made a mistake because *[tex \LARGE \frac{3}{(13)\ +\ 1}\ =\ \frac{3}{14}\ \neq\ \frac{5}{20}\ =\ \frac{5}{(13)\ +\ 7}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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