Question 623632
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Hi,  
 In General {{{A = P(1+r/n)^(nt)}}}
A = Accumulated Amount $4,300
P= principal = $3,800
r= annual rate = .
n= periods per year = 4
t= years = 2
{{{A = P(1+r/n)^(nt)}}}
{{{4300/3800 = (1+r/4)^(4*2)}}}
 log(43/38) =8 log(1 + r/4)
      .0067 = log(1 + r/4)
    10^(.0067) = 1 + r/4    | Solve for r