<PRE><B>Question 623564</B>
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*[tex \LARGE f(-1)\ =\ \frac{1}{9}] and *[tex \LARGE f(0)\ =\ 1]


Where did you get the idea that the difference is 1?  *[tex \LARGE 1\ -\ \frac{1}{9}\ =\ \frac{8}{9}]


Be that as it may:  *[tex \LARGE \frac{f(0)}{f(-1)}\ =\ \frac{1}{\frac{1}{9}}\ =\ 9]; which is to say, the reciprocal of one-ninth is nine.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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