Question 623563
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Distance equals rate times time.  If we let *[tex \LARGE r] represent the speed in the afternoon, the distance he traveled in the morning is *[tex \LARGE 6(r\ -\ 10)] and the distance he traveled in the afternoon is *[tex \LARGE 2r].  These two distances add up to 380, so:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2r\ +\ 6(r\ -\ 10)\ =\ 380]


Solve for *[tex \LARGE r]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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