Question 623557
Given T(x) = 9
.
The above says that for ANY 'x', T(x) is always equal to 9 
So

(a) T(-3) = 9
(b) T(0) = 9
(c) T(2/7) = 9 
(d) T(3) + T(1) = 9 + 9 = 18
(e) T(x + h) = 9
(f) T(3k + 5) = 9