Question 623365
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Hi,  
·The base of an equilateral triangle with side 2a lies along the y-axis such that mid-point of the base is the at the origin.
Note below when a = 1, then {{{sqrt(4 - 1)= sqrt(3)}}} is the distance along the x-axis
Vertices of the Triangle described: (0,a), (0,-a), (a{{{sqrt(3)}}},0)
{{{drawing(300,300,   -6, 6, -6, 6,  grid(1),
circle(0, 1,0.3),
circle(0, -1,0.3),
circle(1.732, 0,0.3),
line(0,1,1.732,0),
line(0,-1,1.732,0),
graph( 300, 300, -6, 6, -6, 6))}}}