Question 623247
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Hi,  ·
A total of $4000 was invested, part{{{highlight(x)}}} of it at 8% interest and the remainder at 9%.  
If the yearly interest amounted to $350, how much was invested at each rate?
 .08·x + .09($4000-x)= $350
            -.01·x = $350 - $360
                 x = -$10/-.01
                 x = $1000, amount at 8%,  $3000 the amount at 9%
and
CHECKING our Answer***
  $80 + $270 = $350