Question 623236
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Hi,
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The length of a field is 6' more that twice it width{{{highlight(x)}}},
If the perimeter is 228', find the dimensions of the field.
 P = 2L + 2W 
Question states***
  2(2x+6') + 2x = 228'
      6x = 216
       x = 36', the width and the length is 78'
and
CHECKING our Answer***
{{{2*36 + 2*78= 228'}}}