Question 623123
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Hi,
(A) Find the 95% confidence interval of the mean score for all 142 golfers.
ME = 1.96[3.84/sqrt(142)]   and   90.46 - ME < {{{mu}}} < 90.46 + ME
(B) Find the 95% confidence interval of the mean score for all golfers if this is a sample of 120 golfers 
ME = 1.96[3.84/sqrt(120)]  and   90.46 - ME < {{{mu}}} < 90.46 + ME
(C) Which confidence interval is larger and why?  for the smaller sample as then ME is larger