Question 623208
Since this is an "expression", you can't "solve" it!
You can factor it though!
{{{x^2y-6xy^2+9y^3}}} Factor a y.
{{{y(x^2-6xy+9y^2)}}} The factor in paretheses is a "perfect square" so it's factorable:
{{{y(x-3y)(x-3y)}}}