Question 623207
This is an "expression" so you can't really "solve" it!
If it were an equation, then you might be able to.
You can, however, factor this expression.
{{{4x^3+4x^2y+xy^2}}} Factor an x.
{{{x(4x^2+4xy+y^2)}}} The factor in parentheses is a "perfect square", so it is factorable...
{{{x(2x+y)(2x+y)}}}