Question 623141
Yes that is correct.  {{{x^2 - y^2 = (x+y)(x-y)}}}<P>
{{{x/(x-y) - 2y^2/(x^2 - y^2) = x/(x-y) - 2y^2/((x+y)(x-y)) = (x(x+y) - 2y^2)/(x^2 - y^2) = (x^2 + xy -2y^2)/(x^2 - y^2)}}}
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