Question 623075
solve 5x^-11=0
I have a=5,b=0,c=-11 with an answer of x=*-square root of 220 over 10
----------
{{{5x^-11 = 0}}}
x = infinity
===================
If you mean
5x^2 - 11 = 0 as is implied by your a = .... 
x^2 = 11/5
x = sqrt(55)/5
x = -sqrt(55)/5
--------------
x^  is meaningless without an exponent.