Question 623027
For Part 1 we need to find how many combinations of 3 choices can be made out of 5 options. This can be done with a tree diagram or we can use the formula for this:
{{{5!/(3!*2!)}}}
which simplifies as follows:
{{{(1*2*3*4*5)/((1*2*3)*(1*2))}}}
{{{(1*cross(2)*cross(3)*4*5)/((1*cross(2)*cross(3))*(1*2))}}}
{{{20/2}}}
{{{10}}}<br>
For Part 2, four out of 6:
{{{6!/(4!*2!)}}}
{{{(1*2*3*4*5*6)/((1*2*3*4)*(1*2))}}}
{{{(1*cross(2)*cross(3)*cross(4)*5*6)/((1*cross(2)*cross(3)*cross(4))*(1*2))}}}
{{{30/2}}}
{{{15}}}<br>
For the total number of ways both parts can be answered:
10*15 = 150