<PRE><B>Question 622902</B>
A silversmith mixed 25 g of a 80% silver alloy with 50 g of a 25% silver alloy. What is the percent concentration of the resulting alloy? (Round to the nearest tenth of a percent.)
.
Let x = concentration
then
.80(25) + .25(50) = x(25+50)
20 + 12.5 = x(75)
32.5 = x(75)
32.5/75 = x
0.433 = x
43.3% = x</PRE>