Question 622926
The sum of the ages of two boys is 18. If 4 times the younger boy's age is subtracted from 3 times the older boy's age, the difference is 12. What are the ages of the two boys?
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let x=older boy's age
18-x=younger boy's age
..
3x-4(18-x)=12
3x-72+4x=12
7x=84
x=12
18-x=6
..
older boy's age=12
younger boy's age=6