<PRE><B>Question 622633</B>
Let the four consecutive numbers be:

n

n + 2

n + 4

n + 6

Add the above:

n + n + 2 n + 4 + n + 6

Combine like terms:

n + n + n + n = 4n

2 + 4 + 6 = 12

4n + 12 = 68

Subtract 12 from each side of the equation.

4n + 12 - 12 = 68 - 12

Combine like terms:

12 - 12 = 0

68 - 12 = 56

4n = 56

Divide each side by 4

4n/4 = 56/4

n = 14

n + 2 = 14 + 2 = 16

n + 4 = 14 + 4 = 18

n + 6 = 14 + 6 = 20

Therefore the four consecutive numbers are:

14, 16, 18 and 20

obuong3@aol.com </PRE>