Question 622542
Let the smaller integer be {{{n}}}.
The greater integer is {{{2*n-3}}} (two times the smaller integer minus 3).
The sum of those two integers is
{{{n+(2n-3)=36}}} --> {{{3n-3=36}}} --(add 3 to both sides)--> {{{3n=39}}} --(divide by 3 both sides) --> {{{highlight(n=13)}}}
So the smaller integer is 13, and the greater integer is
{{{2*13-3=highlight(23)}}}