Question 622502
{{{2 cos(x/2) + 1 = 1}}} --> {{{2 cos(x/2)=0}}} (subtracting 1 from both sides of the equal sign.
{{{2 cos(x/2)=0}}} --> {{{cos(x/2)=0}}}
{{{x/2=pi/2}}}, and {{{x/2=3pi/2}}} are solutions
So are all angles co-terminal to those two, and the whole set can be written as
{{{x/2=(2n+1)*pi/2}}} for all n integers
So the solution set is (multiplying both sides of the equal sign times 2)
{{{x=(2n+1)*pi}}} for all n integers