Question 57397
16x^2-27x-10
Find two numbers whose product is -160 and whose sum is -27.
The numbers are -32 and 5.
Rewrite the trinomial as follows:
=16x^2-32x+5x-10
=16x(x-2)+5(x-2)
=(x-2)(16x+5)
Cheers,
Stan H