Question 7102
One way to assure yourself that these are indeed correct is to draw a right triangle whose hypotenuse is length 2, and whose legs are each length {{{sqrt(2)}}} Since this is an isosceles triangle, the angles opposite the right angle are each 45 degrees. Call them angle A.
 Remember: sohcahtoa ? (no, no, not the indian guide!) it's the acronym for remembering the trigonometric relationships with the sides of the right triangle. h = hypotenuse, o = side opposite, a = side adjacent.
In your triangle, {{{h = 2}}}, {{{o = sqrt(2)}}} and {{{a = sqrt(2)}}} 

Sin = o/h
Cos = a/h
Tan = o/a

From this triangle, you can see that:

{{{Sin A = (sqrt(2))/2}}}
{{{Tan A = (sqrt(2))/sqrt(2)}}} = 1
{{{cosecant A = 2/sqrt(2)}}}
{{{secant A = 2/sqrt(2)}}}
{{{Cotangent A = (sqrt(2))/sqrt(2)}}} = 1