Question 622459
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Let *[tex \LARGE x] represent "another number", then the first number must be *[tex \LARGE 2x\ -\ 2]


The sum of the squares is 193 means:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ \left(2x\ -\ 2\right)^2\ =\ 193]


Expand the squared binomial, collect like terms in the LHS, put the equation in standard form, and then solve the quadratic equation for *[tex \LARGE x]


Hint:  The quadratic factors over the rational numbers, but it may be easier just to use the quadratic formula.  Since you now know the quadratic factors over the rationals (I did it, so I know) you can be assured that the discriminant is a perfect square.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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