Question 622402
Let the age of A be = n + 6

Let the age of B be = n

In five years time:

A = n + 6 + 5

B = n + 5

(n + 6 + 5) + (n + 5)

n + 6 + 5 + n + 5

Combine like terms:

n + n = 2n

6 + 5 + 5 = 16

2n + 16 = 70

Subtract 16 from each side of the equation.

2n + 16 - 16 = 70 - 16

Combine like terms:

16 - 16 = 0

70 - 16 = 54

2n = 54

Divide each side by 2

2n/2 = 54/2

n = 27

n + 6 = 27 + 6 = 33

Therefore:

A is 33 years old and

B is 27 years old.