Question 622385
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Substitute *[tex \LARGE 3a] for *[tex \LARGE x] everywhere you see *[tex \LARGE x] in the definition of the function.  Then simplify.


Example:  *[tex \LARGE f(x)\ =\ x^2\ -\ 5x\ +\ 6], then *[tex \LARGE f(3a)\ =\ (3a)^2\ -\ 5(3a)\ +\ 6\ =\ 9a^2\ -\ 15a\ +\ 6]



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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