Question 622355
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
solving algebraically:  Parabola with V(8,3) and passing thru (5,0) 
 y = a(x -8)^2 + 3
 0 = a(5-8)^2 + 3
 -3/9 = a
 y = (-1/3)(x-8)^2 + 3
 0 = (-1/3)(x-8)^2 + 3
      -3 = (-1/3)(x-8)^2
       (x-8)^2 = 9
        (x-8) = ± 3
          x = 5 and x = 11 
    (11,0) are the coordinates of the other x- intercept.