Question 622299
f(x)=(1)/(√(4x^2-17x+4))
Find the domain and express in interval notation 
info: its 1 over the square root of the numbers listed above
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f(x)=(1)/(√(4x^2-17x+4))
=1/√(4x^2-17x+4)
=1/[√(4x-1)(x-4)]
check for values of x which makes function undefined:
4x-1=0
x≠1/4
or
x-4=0
x≠4
..
check for radican≥0
(4x-1)(x-4)≥0
number line
<..+....1/4....-......4.....+.........>

Domain: (-&#8734;,1/4) U (4,&#8734;)
In other words, all real numbers except x=1/4 and 4 and between x=1/4 and 4 (not including 1/4 and 4)