Question 57355
[x/(x-4)- 1/(x-1)] / [x/(x-1)+ 2/(x-3)]
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Numerator : [x(x-1)-(x-4)]/[(x-4)(x-1)]
=[x^2-x-x+4]/[[x^2-5x+4]
=[x^2-2x+4]/[x^2-5x+4]
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Denominator: [x(x-3+2(x-1)]/[x^2-4x+3]
=[x^2-3x+2x-2]/[x^2-4x+3]
=[x^2-x-2]/[x^2-4x+3]
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Invert the denominator and multiply to get:
[x^2-2x+4/[(x-4)(x-1)] * [(x-3)(x-1)]/[(x-2)(x+1)]
Cancel the (x-1)'s to get:
[(x^2-2x+4)(x-3)]/[(x-4)(x-2)(x+1)]
Cheers,
Stan H.