Question 57385
{{{ ((x^2+2x-15)/(x^2-9))/((x^2+6x+5)/(x^2+4x+3)) }}}
There is a rule that says ...
{{{ (a/b)/(c/d) = ad/bc }}}
So re-write your expression
{{{ ((x^2+2x-15)(x^2+4x+3))/((x^2+6x+5)(x^2-9)) }}}
Factor each polynomial
{{{ (((x+5)(x-3))((x+3)(x+1)))/(((x+5)(x+1))((x-3)(x+3))) }}}
Reduce the fraction ...
{{{ ((x-3)((x+3)(x+1)))/((x+1)((x-3)(x+3))) }}}
{{{ ((x-3)(x+3))/((x-3)(x+3)) }}}
{{{ (x+3)/(x+3) }}}
{{{ 1/1 }}}
{{{ 1 }}}