Question 621931
a piece of wire 14 cm long is cut into two pieces.
 one piece is used to form a square shape and
 the other to form a rectangle shape of which the length is twice its width.
 find the length of the side of the square if the combined area of the two shapes is 5.35cm^2
;
Let x = the width of the rectangle
then
2x = the length of the rectangle
:
Let y = the side of the square
then
he perimeter of the rectangle: 2(2x) + 2x = 6x
The perimeter of the squares = 4y
therefore
6x + 4y = 14
Simplify, divide by 2
3x + 2y = 7
y = {{{(7-3x)/2}}}
:
The area
2x^2 + y^2 = 5.35
y = {{{sqrt(5.35-2x^2)}}}
:
Plot these two equations, you can see there is no intersection, so no solution as the problem is written
{{{ graph( 300, 200, -1, 3, -1, 3, sqrt(5.35-2x^2), (7-3x)/2) }}}