Question 622116
square both sides and the radicals go away. In this case, it is a simple thing to do

{{{sqrt(5x-3) = sqrt(9x-7)}}} now square both sides
{{{(sqrt(5x-3))^2 = (sqrt(9x-7))^2}}}
{{{5x-3 = 9x -7}}}
{{{4 = 4x}}}
{{{1 = x}}}
check your answers by solving the original equations with x = 1 to see if both sides resolve to the same value