Question 622103
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Hi,
 y = -2x^2 + 3, Yes! V(0,3), opening downward as -2 < 0
 y -axis the axis of symmetry, Pt(1,1) on the parabola.
Plot points and use the axis of symmetry to sketch the graph
Might recommend downloading the FREE graph software at http://www.padowan.dk.com
 to check Your work when determining graphs of various functions You will be working with
{{{drawing(300,300,   -6, 6, -6, 6,   grid(1),
circle(0, 3,0.3),
circle(1, 1,0.3),
graph( 300, 300, -6, 6, -6, 6,0,-2x^2 + 3))}}}