Question 622049
Find all real solutions of equation 2x^2 + 4x + 7 = 0.

Does the equation have real solutions? Input Yes or No:

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Find the discriminant, = b^2 - 4ac
Disc = 4^2 - 4*2*7 = 16 - 56
Disc = -40
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If the Disc < 0 there are no real number solutions, 2 complex solutions.
If the Disc = 0 there are 2 real number solutions that are the same.
If the Disc > 0 there are 2 real number solutions that are different.